python - Sort a list of tuples by 2nd item (integer value)

Question

This question already has answers here:

Answer 1

Try using the key keyword with sorted().

sorted([('abc', 121),('abc', 231),('abc', 148), ('abc',221)], key=lambda x: x[1])

key should be a function that identifies how to retrieve the comparable element from your data structure. In your case, it is the second element of the tuple, so we access [1].

For optimization, see jamylak's response using itemgetter(1), which is essentially a faster version of lambda x: x[1].