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recursion - Understanding how recursive functions work

As the title explains I have a very fundamental programming question which I have just not been able to grok yet. Filtering out all of the (extremely clever) "In order to understand recursion, you must first understand recursion." replies from various online threads I still am not quite getting it.

Understanding that when faced with not knowing what we don't know, we can tend to ask the wrong questions or ask the right questions incorrectly I will share what I "think" my question is in hopes that someone with a similar outlook can share some bit of knowledge that will help turn on the recursive light bulb for me!

Here is the function (the syntax is written in Swift):

func sumInts(a: Int, b: Int) -> Int {
    if (a > b) {
        return 0
    } else {
        return a + sumInts(a: a + 1, b: b)
    }
}

We'll use 2 and 5 as our arguments:

println(sumInts(a: 2, b: 5))

Obviously the answer is 14. But I'm not clear on how that value is achieved.

These are my 2 hangups:

  1. The function is called recursively until a condition is met. That condition is a > b. When this condition is met, return 0. At first glance, I would expect the return value to be 0 which is obviously incorrect.

  2. Printing out the value of 'a' on each iteration yields a value which I would expect: 2, 3, 4, 5 (at which point 5+1 > b which meets the first condition: a > b) but I still don't see how the value of 14 is achieved.

My first thought is that something similar to the following is happening magically:

var answer = a;
answer += a+1 until a > b;
return answer;   

So ruling out magic, I'm just not getting something. I would love to understand what's happening more than just implicitly.

If someone could kindly explain what technically happens during this kind of function and why the result isn't 0 and how, eventually, a + sumInts(a: a + 1, b: b) = 14, I would be forever in your debt.

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1.The function is called recursively until a condition is met. That condition is a > b. When this condition is met, return 0. At first glance, I would expect the return value to be 0 which is obviously incorrect.

Here is what the computer computing sumInts(2,5) would think if it were able to:

I want to compute sumInts(2, 5)
for this, I need to compute sumInts(3, 5)
and add 2 to the result.
  I want to compute sumInts(3, 5)
  for this, I need to compute sumInts(4, 5)
  and add 3 to the result.
    I want to compute sumInts(4, 5)
    for this, I need to compute sumInts(5, 5)
    and add 4 to the result.
      I want to compute sumInts(5, 5)
      for this, I need to compute sumInts(6, 5)
      and add 5 to the result.
        I want to compute sumInts(6, 5)
        since 6 > 5, this is zero.
      The computation yielded 0, therefore I shall return 5 = 5 + 0.
    The computation yielded 5, therefore I shall return 9 = 4 + 5.
  The computation yielded 9, therefore I shall return 12 = 3 + 9.
The computation yielded 12, therefore I shall return 14 = 2 + 12.

As you see, some call to the function sumInts actually returns 0 however this not the final value because the computer still has to add 5 to that 0, then 4 to the result, then 3, then 2, as described by the four last sentences of the thoughts of our computer. Note that in the recursion, the computer does not only have to compute the recursive call, it also has to remember what to do with the value returned by the recursive call. There is a special area of computer's memory called the stack where this kind of information is saved, this space is limited and functions that are too recursive can exhaust the stack: this is the stack overflow giving its name to our most loved website.

Your statement seems to make the implicit assumption that the computer forgets what it were at when doing a recursive call, but it does not, this is why your conclusion does not match your observation.

2.Printing out the value of 'a' on each iteration yields a value which I would expect: 2, 3, 4, 5 (at which point 5+1 > b which meets the first condition: a > b) but I still don't see how the value of 14 is achieved.

This is because the return value is not an a itself but the sum of the value of a and the value returned by the recursive call.


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