Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
174 views
in Technique[技术] by (71.8m points)

html - Can I write a CSS selector selecting elements NOT having a certain class or attribute?

I would like to write a CSS selector rule that selects all elements that don't have a certain class. For example, given the following HTML:

<html class="printable">
    <body class="printable">
        <h1 class="printable">Example</h1>
        <nav>
            <!-- Some menu links... -->
        </nav>
        <a href="javascript:void(0)" onclick="javascript:self.print()">Print me!</a>
        <p class="printable">
            This page is super interresting and you should print it!
        </p>
    </body>
</html>

I would like to write a selector that selects all elements that don't have the "printable" class which, in this case, are the nav and a elements.

Is this possible?

NOTE: in the actual HTML where I would like to use this, there are going to be a lot more elements that don't have the "printable" class than do (I realize it's the other way around in the above example).

Question&Answers:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Typically you add a class selector to the :not() pseudo-class like so:

:not(.printable) {
    /* Styles */
}

:not([attribute]) {
    /* Styles */
}

But if you need better browser support (IE8 and older don't support :not()), you're probably better off creating style rules for elements that do have the "printable" class. If even that isn't feasible despite what you say about your actual markup, you may have to work your markup around that limitation.

Keep in mind that, depending on the properties you're setting in this rule, some of them may either be inherited by descendants that are .printable, or otherwise affect them one way or another. For example, although display is not inherited, setting display: none on a :not(.printable) will prevent it and all of its descendants from displaying, since it removes the element and its subtree from layout completely. You can often get around this by using visibility: hidden instead which will allow visible descendants to show, but the hidden elements will still affect layout as they originally did. In short, just be careful.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...