You can do exactly the same call with Swift:
Swift 4 & Swift 5
In Swift 4 String is a collection of Character
values, it wasn't like this in Swift 2 and 3, so you can use this more concise code1:
let string = "hello Swift"
if string.contains("Swift") {
print("exists")
}
Swift 3.0+
var string = "hello Swift"
if string.range(of:"Swift") != nil {
print("exists")
}
// alternative: not case sensitive
if string.lowercased().range(of:"swift") != nil {
print("exists")
}
Older Swift
var string = "hello Swift"
if string.rangeOfString("Swift") != nil{
println("exists")
}
// alternative: not case sensitive
if string.lowercaseString.rangeOfString("swift") != nil {
println("exists")
}
I hope this is a helpful solution since some people, including me, encountered some strange problems by calling containsString()
.1
PS. Don't forget to import Foundation
Footnotes
- Just remember that using collection functions on Strings has some edge cases which can give you unexpected results, e. g. when dealing with emojis or other grapheme clusters like accented letters.
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