java - How to execute IN() SQL queries with Spring's JDBCTemplate effectively?

Question

I was wondering if there is a more elegant way to do IN() queries with Spring's JDBCTemplate. Currently I do something like that:

StringBuilder jobTypeInClauseBuilder = new StringBuilder();
for(int i = 0; i < jobTypes.length; i++) {
    Type jobType = jobTypes[i];

    if(i != 0) {
        jobTypeInClauseBuilder.append(',');
    }

    jobTypeInClauseBuilder.append(jobType.convert());
}

Which is quite painful since if I have nine lines just for building the clause for the IN() query. I would like to have something like the parameter substitution of prepared statements

Answer 1

You want a parameter source:

Set<Integer> ids = ...;

MapSqlParameterSource parameters = new MapSqlParameterSource();
parameters.addValue("ids", ids);

List<Foo> foo = getJdbcTemplate().query("SELECT * FROM foo WHERE a IN (:ids)",
     parameters, getRowMapper());

This only works if getJdbcTemplate() returns an instance of type NamedParameterJdbcTemplate