Let's say you want to scale a range [min,max]
to [a,b]
. You're looking for a (continuous) function that satisfies
f(min) = a
f(max) = b
In your case, a
would be 1 and b
would be 30, but let's start with something simpler and try to map [min,max]
into the range [0,1]
.
Putting min
into a function and getting out 0 could be accomplished with
f(x) = x - min ===> f(min) = min - min = 0
So that's almost what we want. But putting in max
would give us max - min
when we actually want 1. So we'll have to scale it:
x - min max - min
f(x) = --------- ===> f(min) = 0; f(max) = --------- = 1
max - min max - min
which is what we want. So we need to do a translation and a scaling. Now if instead we want to get arbitrary values of a
and b
, we need something a little more complicated:
(b-a)(x - min)
f(x) = -------------- + a
max - min
You can verify that putting in min
for x
now gives a
, and putting in max
gives b
.
You might also notice that (b-a)/(max-min)
is a scaling factor between the size of the new range and the size of the original range. So really we are first translating x
by -min
, scaling it to the correct factor, and then translating it back up to the new minimum value of a
.
Hope this helps.
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