Sort a two dimensional array based on one column
The first column is a date of format "yyyy.MM.dd HH:mm" and the second column is a String.
Since you say 2-D array, I assume "date of format ..." means a String. Here's code for sorting a 2-D array of String[][]:
import java.util.Arrays;
import java.util.Comparator;
public class Asdf {
public static void main(final String[] args) {
final String[][] data = new String[][] {
new String[] { "2009.07.25 20:24", "Message A" },
new String[] { "2009.07.25 20:17", "Message G" },
new String[] { "2009.07.25 20:25", "Message B" },
new String[] { "2009.07.25 20:30", "Message D" },
new String[] { "2009.07.25 20:01", "Message F" },
new String[] { "2009.07.25 21:08", "Message E" },
new String[] { "2009.07.25 19:54", "Message R" } };
Arrays.sort(data, new Comparator<String[]>() {
@Override
public int compare(final String[] entry1, final String[] entry2) {
final String time1 = entry1[0];
final String time2 = entry2[0];
return time1.compareTo(time2);
}
});
for (final String[] s : data) {
System.out.println(s[0] + " " + s[1]);
}
}
}
Output:
2009.07.25 19:54 Message R
2009.07.25 20:01 Message F
2009.07.25 20:17 Message G
2009.07.25 20:24 Message A
2009.07.25 20:25 Message B
2009.07.25 20:30 Message D
2009.07.25 21:08 Message E
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