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css - Possible to use border-radius together with a border-image which has a gradient?

I'm styling an input field which has a rounded border (border-radius), and attempting to add a gradient to said border. I can successfully make the gradient and the rounded border, however neither work together. It's either rounded with no gradient, or a border with a gradient, but no rounded corners.

-webkit-border-radius: 5px;
-webkit-border-image: -webkit-gradient(linear, 0 0, 0 100%, from(#b0bbc4), to(#ced9de)) 1 100%;

Is there anyway to have both CSS properties work together, or is this not possible?

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This is possible, and it does not require extra markup, but uses an ::after pseudo-element.

                                   screenshot

It involves putting a pseudo-element with a gradient background below and clipping that. This works in all current browsers without vendor prefixes or hacks (even IE), but if you want to support vintage versions of IE, you should either consider solid color fallbacks, javascript, and/or custom MSIE CSS extensions (i.e., filter, CSSPie-like vector trickery, etc).

Here's a live example (jsfiddle version):

@import url('//raw.githubusercontent.com/necolas/normalize.css/master/normalize.css');

html {
    /* just for showing that background doesn't need to be solid */
    background: linear-gradient(to right, #DDD 0%, #FFF 50%, #DDD 100%);
    padding: 10px;
}

.grounded-radiants {
    position: relative;
    border: 4px solid transparent;
    border-radius: 16px;
    background: linear-gradient(orange, violet);
    background-clip: padding-box;
    padding: 10px;
    /* just to show box-shadow still works fine */
    box-shadow: 0 3px 9px black, inset 0 0 9px white;
}

.grounded-radiants::after {
    position: absolute;
    top: -4px; bottom: -4px;
    left: -4px; right: -4px;
    background: linear-gradient(red, blue);
    content: '';
    z-index: -1;
    border-radius: 16px;
}
<p class="grounded-radiants">
    Some text is here.<br/>
    There's even a line break!<br/>
    so cool.
</p>

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