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Initializing member variables using the same name for constructor arguments as for the member variables allowed by the C++ standard?

I figured out that it's possible to initialize the member variables with a constructor argument of the same name as show in the example below.

#include <cstdio>
#include <vector>

class Blah {
    std::vector<int> vec;

public:
    Blah(std::vector<int> vec): vec(vec)
    {}

    void printVec() {

        for(unsigned int i=0; i<vec.size(); i++)
            printf("%i ", vec.at(i));

        printf("
");
    }
};

int main() {

    std::vector<int> myVector(3);

    myVector.at(0) = 1;
    myVector.at(1) = 2;
    myVector.at(2) = 3;

    Blah blah(myVector);

    blah.printVec();

    return 0;
}

g++ 4.4 with the arguments -Wall -Wextra -pedantic gives no warning and works correctly. It also works with clang++. I wonder what the C++ standard says about it? Is it legal and guaranteed to always work?

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I wonder what the C++ standard says about it? Is it legal and guaranteed to always work?

Yes. That is perfectly legal. Fully Standard conformant.

Blah(std::vector<int> vec): vec(vec){}
                             ^   ^                           
                             |   |
                             |    this is the argument to the constructor
                             this is your member data

Since you asked for the reference in the Standard, here it is, with an example.

§12.6.2/7

Names in the expression-list of a mem-initializer are evaluated in the scope of the constructor for which the mem-initializer is specified.

[Example:
class X {
 int a;
 int b;
 int i;
 int j;
 public:
 const int& r;
  X(int i): r(a), b(i), i(i), j(this->i) {}
                      //^^^^ note this (added by Nawaz)
};

initializes X::r to refer to X::a, initializes X::b with the value of the constructor parameter i, initializes X::i with the value of the constructor parameter i, and initializes X::j with the value of X::i; this takes place each time an object of class X is created. ]

[Note: because the mem-initializer are evaluated in the scope of the constructor, the this pointer can be used in the expression-list of a mem-initializer to refer to the object being initialized. ]

As you can see, there're other interesting thing to note in the above example, and the commentary from the Standard itself.


BTW, as side note, why don't you accept the parameter as const reference:

 Blah(const std::vector<int> & vec): vec(vec) {}
      ^^^^const              ^reference

It avoids unneccessary copy of the original vector object.


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