c++ - How to know the exact line of code where an exception has been caused?

Question

If I generate an exception on my own, I can include any info into the exception: a number of code line and name of source file. Something like this:

throw std::exception("myFile.cpp:255");

But what's with unhandled exceptions or with exceptions that were not generated by me?

Answer 1

A better solution is to use a custom class and a macro. :-)

#include <iostream>
#include <sstream>
#include <stdexcept>
#include <string>

class my_exception : public std::runtime_error {
    std::string msg;
public:
    my_exception(const std::string &arg, const char *file, int line) :
    std::runtime_error(arg) {
        std::ostringstream o;
        o << file << ":" << line << ": " << arg;
        msg = o.str();
    }
    ~my_exception() throw() {}
    const char *what() const throw() {
        return msg.c_str();
    }
};
#define throw_line(arg) throw my_exception(arg, __FILE__, __LINE__);

void f() {
    throw_line("Oh no!");
}

int main() {
    try {
        f();
    }
    catch (const std::runtime_error &ex) {
        std::cout << ex.what() << std::endl;
    }
}