java - Sort arrays of primitive types in descending order

Question

I've got a large array of primitive types (double). How do I sort the elements in descending order?

Unfortunately the Java API doesn't support sorting of primitive types with a Comparator.

The first approach that probably comes to mind is to convert it to a list of objects (boxing):

double[] array = new double[1048576];    
Arrays.stream(array).boxed().sorted(Collections.reverseOrder())…

However, boxing each primitive in the array is too slow and causes a lot of GC pressure!

Another approach would be to sort and then reverse:

double[] array = new double[1048576];
...
Arrays.sort(array);
// reverse the array
for (int i = 0; i < array.length / 2; i++) {
     // swap the elements
     double temp = array[i];
     array[i] = array[array.length - (i + 1)];
     array[array.length - (i + 1)] = temp;
}

This approach is also slow - particularly if the array is already sorted quite well.

What's a better alternative?

Answer 1

Java Primitive includes functionality for sorting primitive arrays based on a custom comparator. Using it, and Java 8, your sample could be written as:

double[] array = new double[1048576];
...
Primitive.sort(array, (d1, d2) -> Double.compare(d2, d1), false);

If you're using Maven, you can include it with:

<dependency>
    <groupId>net.mintern</groupId>
    <artifactId>primitive</artifactId>
    <version>1.2.1</version>
</dependency>

When you pass false as the third argument to sort, it uses an unstable sort, a simple edit of Java's built-in dual-pivot quicksort. This means that the speed should be close to that of built-in sorting.

Full disclosure: I wrote the Java Primitive library.