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Using port number in Windows host file

After installing TeamViewer, I have changed the wampserver port to 8080, so the address is http://localhost:8080.

For the host file located at C:WINDOWSsystem32driversetc, I have also made the change as below

BEFORE
127.0.0.1 www.example.com

AFTER
127.0.0.1:8080 www.example.com

When I access www.example.com, it doesn't redirect to my wampserver, how can I fix it?

Question&Answers:os

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I managed to achieve this by using Windows included Networking tool netsh.

As Mat points out : The hosts file is for host name resolution only, so a combination of the two did the trick for me.

Example


Overview

example.app:80
 |                           <--Link by Hosts File
 +--> 127.65.43.21:80
       |                     <--Link by netsh Utility
       +--> localhost:8081

Actions

  • Started my server on localhost:8081
  • Added my "local DNS" in the hosts file as a new line
    • 127.65.43.21 example.app
      • Any free address in the network 127.0.0.0/8 (127.x.x.x) can be used.
      • Note: I am assuming 127.65.43.21:80 is not occupied by another service.
      • You can check with netstat -a -n -p TCP | grep "LISTENING"
  • added the following network configuration with netsh command utility
    • netsh interface portproxy add v4tov4 listenport=80 listenaddress=127.65.43.21 connectport=8081 connectaddress=127.0.0.1
  • I can now access the server at http://example.app

Notes:
- These commands/file modifications need to be executed with Admin rights

- netsh portproxy needs ipv6 libraries even only to use v4tov4, typically they will also be included by default, otherwise install them using the following command: netsh interface ipv6 install


You can see the entry you have added with the command:

netsh interface portproxy show v4tov4

You can remove the entry with the following command:

netsh interface portproxy delete v4tov4 listenport=80 listenaddress=127.65.43.21


Links to Resources:


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