This is called a local class.
2 is the easy one: yes, a class file will be generated.
1 and 3 are kind of the same question. You would use a local class where you never need to instantiate one or know about implementation details anywhere but in one method.
A typical use would be to create a throw-away implementation of some interface. For example you'll often see something like this:
//within some method
taskExecutor.execute( new Runnable() {
public void run() {
classWithMethodToFire.doSomething( parameter );
}
});
If you needed to create a bunch of these and do something with them, you might change this to
//within some method
class myFirstRunnableClass implements Runnable {
public void run() {
classWithMethodToFire.doSomething( parameter );
}
}
class mySecondRunnableClass implements Runnable {
public void run() {
classWithMethodToFire.doSomethingElse( parameter );
}
}
taskExecutor.execute(new myFirstRunnableClass());
taskExecutor.execute(new mySecondRunnableClass());
Regarding interfaces: I'm not sure if there's a technical issue that makes locally-defined interfaces a problem for the compiler, but even if there isn't, they wouldn't add any value. If a local class that implements a local interface were used outside the method, the interface would be meaningless. And if a local class was only going to be used inside the method, both the interface and the class would be implemented within that method, so the interface definition would be redundant.
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