This is not a duplicate of "How to safely call an async method in C# without await".
How do I nicely suppress the following warning?
warning CS4014: Because this call is not awaited, execution of the current method continues before the call is completed. Consider applying the 'await' operator to the result of the call.
A simple example:
static async Task WorkAsync()
{
await Task.Delay(1000);
Console.WriteLine("Done!");
}
static async Task StartWorkAsync()
{
WorkAsync(); // I want fire-and-forget
// more unrelated async/await stuff here, e.g.:
// ...
await Task.Delay(2000);
}
What I tried and did not like:
static async Task StartWorkAsync()
{
#pragma warning disable 4014
WorkAsync(); // I want fire-and-forget here
#pragma warning restore 4014
// ...
}
static async Task StartWorkAsync()
{
var ignoreMe = WorkAsync(); // I want fire-and-forget here
// ...
}
Updated, since the original accepted answer has been edited, I've changed the accepted answer to the one using C# 7.0 discards, as I don't think ContinueWith
is appropriate here. Whenever I need to log exceptions for fire-and-forget operations, I use a more elaborate approach proposed by Stephen Cleary here.
Question&Answers:
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