Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
835 views
in Technique[技术] by (71.8m points)

Python, why does this function go into an infinite loop

def new_if (pred,then_clause,else_clause):

    if pred:
        then_clause
    else:
        else_clause

def p(x):
    new_if(x>5,print(x),p(2*x))

p(1)

I think the function should stop once x reaches 8 and 8 is printed out.

Thanks a lot for helping

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Your code doesn't do what you think it does.

Every time you call p it executes the code inside that method, which in your case calls new_if with some arguments. However you are evaluating those arguments immediately, which means before entering new_if your code is executing print(x) and p(2*x). This causes p to get called again, repeating the process.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...