Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
331 views
in Technique[技术] by (71.8m points)

c - confusion regarding range of char

As we know that the range of char is -128 to 127.

The 2's compliment of -128 and the binary of 128 is same, which is

10000000

So why the range of char is -128 to 127 but not -127 to 128 .
Where as in case of int , 128 and -128 both are different.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

In twos-complement notation, whenever the high-order bit is 1, the number is negative. So the biggest positive number is

01111111 = 127

and the smallest negative number is

10000000 = -128

The same thing happens for int, but its range is much larger. The biggest positive int is

01111111 11111111 11111111 11111111 = 2147483647

and the smallest negative int is

10000000 00000000 00000000 00000000 = -2147483648

As you can see, in both cases, the smallest negative is 1 more than the biggest positive.

You might be wondering, If there are the same number of bits other than the sign bit, why are there more negative numbers than positives? That's because you're not counting 0. It has 0 in the high-order bit, so it's considered positive in this notation. When you include that, there are 128 negative chars, and 128 non-negative chars, and they balance equally.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...