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in Technique[技术] by (71.8m points)

Android: Display string with textView

hello i am trying to display a string with a TextView. i am doing this dynamically and this is the code:

   LinearLayout layout=(LinearLayout) this.findViewById(R.id.Layout);
   EditText  editText=(EditText) this.findViewById(R.id.textView);
   Button        button=(Button) this.findViewById(R.id.btnAdd);

    LayoutParams lparams = new LayoutParams(
            LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);
            TextView tv=new TextView(this);
            tv.setLayoutParams(lparams);
            tv.setText(display);
            this.layout.addView(tv);

,but it hits an error on this.layout.addView(tv); Can you please tell me what i am doing wrong?

Thanks a lot in advance!

Update(full activity code):

public class CalendarDate extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_calendar_date);
    Bundle extras = getIntent().getExtras();

    String dday = extras.getString("currentday");
    String dmonth =extras.getString("currentmonth");
    String dyear = extras.getString("currentyear");

    ActionBar ab = getActionBar();


    ab.setTitle(dday+"/"+dmonth+"/"+dyear );



    Bundle extraz =getIntent().getExtras();


    String display = extras.getString("EXTRA_MESSAGE");

    setContentView(R.layout.activity_calendar_date);

   LinearLayout layout=(LinearLayout) this.findViewById(R.id.Layout);
   EditText  editText=(EditText) this.findViewById(R.id.textView);
   Button        button=(Button) this.findViewById(R.id.btnAdd);

    LayoutParams lparams = new LayoutParams(
            LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);
            TextView tv=new TextView(this);
            tv.setLayoutParams(lparams);
            tv.setText(display);
            layout.addView(tv);
}
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by (71.8m points)

Remove this, just layout.addView(tv);. Use this for referencing instance variables only. (Variables in the class outside of any methods)


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