Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
233 views
in Technique[技术] by (71.8m points)

jasper reports - SQL subSelect Statement issue in iReport

I am using iReport to write custom reports and have ran into an issue.

I am attempting to alter an existing report by adding the line of code that is:

LEFT JOIN (select info from customfieldview where cftableid = 97022306 and recordid = so.id and cfname = 'SIN')

The field and table names are all correct but for whatever reason it is saying that my "WHERE" statement is messed up. Which with iReport, it's debugger usually says the issue is the line below the actual problem and the line before my WHERE statement just happens to be my subSELECT statement.

I will post my SQL and a photo highlighting my issue.

Is my subSelect statement formatted incorrectly?

SELECT (case when $P{ckShowHistoricalProductNumber} = 1 then soitem.productnum else product.num end) AS soitemproductnum, soitem.description AS soitemdescription,
(case when soitem.uomid != product.uomid then ((postsoitem.qty*uomconversion.multiply)/uomconversion.factor) else postsoitem.qty end) AS postsoitemqty,
producttree.name AS producttreename,
(CASE WHEN soitem.uomid != product.uomid then (soitem.unitprice/uomconversion.multiply)*uomconversion.factor else soitem.unitprice end) + (soitem.adjustamount / (CASE WHEN soitem.qtytofulfill = 0
                                                        THEN 1
                                                        ELSE soitem.qtytofulfill END)) AS soitemunitprice, soitem.typeid AS soitemtypeid,
company.name AS company, uom.code AS uomcode, currency.symbol

FROM soitem
LEFT JOIN postsoitem ON soitem.id = postsoitem.soitemid
JOIN postso on postsoitem.postsoid = postso.id
JOIN product ON soitem.productid = product.id
LEFT JOIN producttotree ON product.id = producttotree.productid
LEFT JOIN producttree ON producttotree.producttreeid = producttree.id
LEFT JOIN uom ON product.uomid = uom.id
LEFT JOIN uomconversion on product.uomid = uomconversion.touomid and soitem.uomid = uomconversion.fromuomid
INNER JOIN company ON company.id = 1
LEFT JOIN currency ON currency.homeCurrency = 1
LEFT JOIN (select info from customfieldview where cftableid = 97022306 and recordid = so.id and cfname = 'SIN')

WHERE postso.postdate BETWEEN $P{dateRange1} AND $P{dateRange2}
AND soitem.typeid IN (10,11,12,21,30,31,40,50,60,70,80)
AND ((COALESCE(producttreeid,0) IN ($P!{productTree1})) OR ((COALESCE(producttreeid,0) LIKE $P{productTree2})))
AND (CASE WHEN $P!{ckShowEachProductOnce} =1 then (Select first 1 producttree.id
       FROM product AS p1
       LEFT JOIN producttotree ON p1.id = producttotree.productid
       LEFT JOIN producttree ON producttotree.producttreeid = producttree.id
       WHERE p1.id = product.id
       AND ((COALESCE(producttreeid,0) IN ($P!{productTree1})) OR ((COALESCE(producttreeid,0) LIKE $P{productTree2})))) else producttree.id end) = producttree.id

enter image description here

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

It turns out that the issue was the way I was programming the subQuery.

I was using LEFT JOIN (select info from customfieldview where cftableid = 97022306 and recordid = so.id and cfname = 'SIN')

and saying it was a subQuery when in fact because it was being use in the FROM condition/arguement then it is actually a Derived Table.

I did not know there was a difference!

Thank you guys for the input and helpful tips!


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...