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parameter passing - Java pass by reference

What is the difference between this 2 codes:

Code A:

Foo myFoo;
myFoo = createfoo();

where

public Foo createFoo()
{
   Foo foo = new Foo();
   return foo;
}

Vs. Code B:

Foo myFoo;
createFoo(myFoo);

public void createFoo(Foo foo)
{
   Foo f = new Foo();
   foo = f;
}

Are there any differences between these 2 pieces of codes?

Question&Answers:os

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1 Reply

0 votes
by (71.8m points)

Java always passes arguments by value NOT by reference.


Let me explain this through an example:

public class Main
{
     public static void main(String[] args)
     {
          Foo f = new Foo("f");
          changeReference(f); // It won't change the reference!
          modifyReference(f); // It will modify the object that the reference variable "f" refers to!
     }
     public static void changeReference(Foo a)
     {
          Foo b = new Foo("b");
          a = b;
     }
     public static void modifyReference(Foo c)
     {
          c.setAttribute("c");
     }
}

I will explain this in steps:

  1. Declaring a reference named f of type Foo and assign it to a new object of type Foo with an attribute "f".

    Foo f = new Foo("f");
    

    enter image description here

  2. From the method side, a reference of type Foo with a name a is declared and it's initially assigned to null.

    public static void changeReference(Foo a)
    

    enter image description here

  3. As you call the method changeReference, the reference a will be assigned to the object which is passed as an argument.

    changeReference(f);
    

    enter image description here

  4. Declaring a reference named b of type Foo and assign it to a new object of type Foo with an attribute "b".

    Foo b = new Foo("b");
    

    enter image description here

  5. a = b is re-assigning the reference a NOT f to the object whose its attribute is "b".

    enter image description here


  6. As you call modifyReference(Foo c) method, a reference c is created and assigned to the object with attribute "f".

    enter image description here

  7. c.setAttribute("c"); will change the attribute of the object that reference c points to it, and it's same object that reference f points to it.

    enter image description here

I hope you understand now how passing objects as arguments works in Java :)


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