The best way to do this would be to use the glue
package. This allows you to easily assign variable names based on strings:
library(tidyverse)
library(glue)
> df <- data.frame(
sample_id = c('SB013', 'SB014', 'SB013', 'SB014', 'SB015', 'SB016', 'SB016'),
IN = c(1,2,3,4,5,6,7),
OUT = c(rep('out',7)))
> df
sample_id IN OUT
1 SB013 1 out
2 SB014 2 out
3 SB013 3 out
4 SB014 4 out
5 SB015 5 out
6 SB016 6 out
7 SB016 7 out
> df %>% mutate(`SB013` = ifelse(sample_id == 'SB013', IN, OUT))
sample_id IN OUT SB013
1 SB013 1 out 1
2 SB014 2 out out
3 SB013 3 out 3
4 SB014 4 out out
5 SB015 5 out out
6 SB016 6 out out
7 SB016 7 out out
Note that in this case, the dplyr
command if_else
won't work because IN
and OUT
are of different types. If it is a large dataset, I would suggest using a function with vectorisation (map
or lapply
), but if there are only 4 unique sample_id
:
> list_of_ids <-
df %>%
distinct(sample_id) %>%
unlist() %>%
unname()
> list_of_ids
[1] "SB013" "SB014" "SB015" "SB016"
> for(current_id in list_of_ids){
df <-
df %>%
mutate('{current_id}' := ifelse(sample_id == current_id, IN, OUT))
}
> df
sample_id IN OUT SB013 SB014 SB015 SB016
1 SB013 1 out 1 out out out
2 SB014 2 out out 2 out out
3 SB013 3 out 3 out out out
4 SB014 4 out out 4 out out
5 SB015 5 out out out 5 out
6 SB016 6 out out out out 6
7 SB016 7 out out out out 7
In future, please add sample data and expected output to your question.
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