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c++ - Replace cout<<"string" with cout<<"string"<<endl in cpp

I want to replace each cout occurring in a program with same but concatenated with endl. I'm trying to use macros for this but unable to figure that out how to do that. Please help!

Is there a way to get complete line written in program and just concat << endl with it? Note if endl is already written by programmer, no endl will be concatenated.

If any other better method possible, please suggest.

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Just make a function template:

template<typename T>
void printLn(T const & v, std::ostream & os = std::cout)
{
    os << v << std::endl;
}

If you wanna get fancy with it and allow multiple arguments, and C++11 is available to you:

void printLn(std::ostream & os)
{
    os << std::endl;
}

template<typename T, typename... Args>
void printLn(std::ostream & os, T const & v, Args&&... args)
{
    os << v;
    printLn(os, std::forward<Args>(args)...);
}

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