Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
301 views
in Technique[技术] by (71.8m points)

Python error - list index out of range?

Anyone help me see why I keep getting "list index out of range" as an error ??

def printInfo(average):
    average.sort()  # sorts the list of tuples 
    average.reverse()  # reverses the list of tuples 
    print('	Date		Average Price')
    for i in range(6):
        print("	{:.2f}".format(average[i][2], average[i][1], average[i][0]))
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You hard coded the range of your loop and it is probably greater than the length of the list

A quick fix is

def printInfo(average):
    average.sort()  # sorts the list of tuples 
    average.reverse()  # reverses the list of tuples 
    print('	Date		Average Price')
    for i in range(len(average)): #Change was here
        print("	{:.2f}".format(average[i][2], average[i][1], average[i][0]))

however, a better fix is to use iteration:

def printInfo(average):
    average.sort()  # sorts the list of tuples 
    average.reverse()  # reverses the list of tuples 
    print('	Date		Average Price')
    for a in average: # loops through each item of average
        print("	{:.2f}".format(a[2], a[1], a[0]))

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...