I'm having mistakes do not know where error
Having trouble using JavaScript or Ajax and text display the same page
Please help me in the wrong reform
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>pop up example</title>
<script src="//code.jquery.com/jquery-1.11.2.min.js"></script>
<script type="text/javascript">
document.getElementById('myform').addEventListener("submit",upload);
function upload()
{
var xhr = new XMLHttpRequest();
xhr.open("POST","/upload.php",true);
{
var formdata = new formData(myform);
xhr.send(formdata);
}
xhr.onreadystatechange = function(){
if(xhr.readyState == 4 && xhr.status == 200)
{
//some code to check if submission succeeded
url = xhr.responseText();
if(url == 'failed')
Console.log('upload failed'); // do something for failure
else
document.getElementById('urlBox').innerHTML = url;
}
}; return false;
}
</script>
</head>
<body>
<form id="myform" method="POST" action=<?php ($_SERVER["PHP_SELF"]); ?>>
<p>chose url:
<select size="1" name="D1">
<option value="google_drive">google drive</option>
<option value="clody">clody</option>
</select>
<input type="text" name="T1" size="40">
<input type="submit" value="go" name="B1">
<input type="reset" value="reset" name="B2">
</p>
</form>
</body>
</html>
and this upload.php file
<?php
if(!empty($_POST['D1']) && !empty($_POST['T1'])){
$providers = array(
'google_drive' => 'Goole drive^https://drive.google.com/file/d/{replace}/view',
'clody' => 'Cloudy^https://www.cloudy.ec/embed.php?id={replace}'
);
if(isset($providers[$_POST['D1']])){
$url = str_replace('{replace}', $_POST['T1'], $providers[$_POST['D1']]);
echo "$url";
}
}
else{
echo "failed";
}
?>
and thank you all
See Question&Answers more detail:
os 与恶龙缠斗过久,自身亦成为恶龙；凝视深渊过久,深渊将回以凝视…
