c++ - How do I avoid implicit conversions on non-constructing functions?

Question

How do I avoid implicit casting on non-constructing functions?
I have a function that takes an integer as a parameter,
but that function will also take characters, bools, and longs.
I believe it does this by implicitly casting them.
How can I avoid this so that the function only accepts parameters of a matching type, and will refuse to compile otherwise?
There is a keyword "explicit" but it does not work on non-constructing functions. :
what do I do?

The following program compiles, although I'd like it not to:

#include <cstdlib>

//the function signature requires an int
void function(int i);

int main(){

    int i{5};
    function(i); //<- this is acceptable

    char c{'a'};
    function(c); //<- I would NOT like this to compile

    return EXIT_SUCCESS;
}

void function(int i){return;}

*please be sure to point out any misuse of terminology and assumptions

Answer 1

Define function template which matches all other types:

void function(int); // this will be selected for int only

template <class T>
void function(T) = delete; // C++11 

This is because non-template functions with direct matching are always considered first. Then the function template with direct match are considered - so never function<int> will be used. But for anything else, like char, function<char> will be used - and this gives your compilation errrors:

void function(int) {}

template <class T>
void function(T) = delete; // C++11 


int main() {
   function(1);
   function(char(1)); // line 12
} 

ERRORS:

prog.cpp: In function 'int main()':
prog.cpp:4:6: error: deleted function 'void function(T) [with T = char]'
prog.cpp:12:20: error: used here

This is C++03 way:

// because this ugly code will give you compilation error for all other types
class DeleteOverload
{
private:
    DeleteOverload(void*);
};


template <class T>
void function(T a, DeleteOverload = 0);

void function(int a)
{}