How to normalize the path(delete all repeated '/') in C

Question

I am coding a program, that deletes all redundant / in the path of the file. In other words ///a/////b should become /a/b. I can delete all repeated /, but can't fully wrap my head about how to leave only one slash WITHOUT any standard function or indexation operation. Can someone fix my code, please?

#include <stdio.h>

//      ///a/////b
//      a/b/a
//      aa///b/a
void normalize_path(char *buf) {
    int k = 0, counter = 0;
    for (int i = 0; buf[i]; i++) {
        buf[i] = buf[i + k];

        if (buf[i] == '/') {
            ++counter;
            if (counter > 1) {
                --i;
                ++k;
            } else {
                ++k;
            }
        } else {
            counter = 0;
        }
    }
}



int main() {
    char path[100];
    scanf("%s", path);
    printf("String before the function: %s
", path);
    normalize_path(path);
    printf("String after the function is used: %s
", path);
    return 0;
}

Answer 1

You can keep track if the previous character is slash, and add characters to the result if and only if at least either one of previous and current characters is not shash.

#include <stdio.h>

//      ///a/////b
//      a/b/a
//      aa///b/a
void normalize_path(char *buf) {
    char *in = buf, *out = buf;
    int prev_is_slash = 0;
    for (; *in != ''; in++) {
        if (!prev_is_slash || *in != '/') *(out++) = *in;
        prev_is_slash = *in == '/';
    }
    *out = '';
}

int main() {
    char path[100];
    scanf("%s", path);
    printf("String before the function: %s
", path);
    normalize_path(path);
    printf("String after the function is used: %s
", path);
    return 0;
}