Parsing variables from config file in Bash

Question

Having the following content in a file:

VARIABLE1="Value1"
VARIABLE2="Value2"
VARIABLE3="Value3"

I need a script that outputs the following:

Content of VARIABLE1 is Value1
Content of VARIABLE2 is Value2
Content of VARIABLE3 is Value3

Any ideas?

Answer 1

Since your config file is a valid shell script, you can source it into your current shell:

. config_file
echo "Content of VARIABLE1 is $VARIABLE1"
echo "Content of VARIABLE2 is $VARIABLE2"
echo "Content of VARIABLE3 is $VARIABLE3"

Slightly DRYer, but trickier

. config_file
for var in VARIABLE1 VARIABLE2 VARIABLE3; do
    echo "Content of $var is ${!var}"
done