swift - Sort Objects in Array by date

Question

I have an array containing an object called HistoryObject and it has properties such as "date", "name", etc.

I am sorting the array like so:

 let sortedArray = HistoryArray.sort({ $0.date.compare($1.date) == NSComparisonResult.OrderedDescending})

which is supposed to sort the date from newer to oldest. For example:

• Jun 30, 2016
• Jun 29, 2016

etc..

But when my array contains "Jul 2, 2016" the sorted array becomes:

• Jun 30, 2016
• Jun 29, 2016
• Jul 2, 2016

Where "Jul 2, 2016" should be on top after sorting, now it's on the bottom? How can I fix this problem?

Answer 1

Using Swift 4 & Swift 3

let testArray = ["25 Jun, 2016", "30 Jun, 2016", "28 Jun, 2016", "2 Jul, 2016"]
var convertedArray: [Date] = []

var dateFormatter = DateFormatter()
dateFormatter.dateFormat = "dd MM, yyyy"// yyyy-MM-dd"

for dat in testArray {
    let date = dateFormatter.date(from: dat)
    if let date = date {
        convertedArray.append(date)
    }
}

var ready = convertedArray.sorted(by: { $0.compare($1) == .orderedDescending })

print(ready)

Using Swift 2

For example you have the array with dates and another 1 array, where you will save the converted dates:

var testArray = ["25 Jun, 2016", "30 Jun, 2016", "28 Jun, 2016", "2 Jul, 2016"]
var convertedArray: [NSDate] = []

After that we convert the dates:

var dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "dd MM, yyyy"// yyyy-MM-dd"

for dat in testArray {
    var date = dateFormatter.dateFromString(dat)
    convertedArray.append(date!)
}

And the result:

var ready = convertedArray.sort({ $0.compare($1) == .OrderedDescending })

print(ready)