There was no solution with python code and I recently had to read zips in pyspark. And, while searching how to do that I came across this question. So, hopefully this'll help others.
import zipfile
import io
def zip_extract(x):
in_memory_data = io.BytesIO(x[1])
file_obj = zipfile.ZipFile(in_memory_data, "r")
files = [i for i in file_obj.namelist()]
return dict(zip(files, [file_obj.open(file).read() for file in files]))
zips = sc.binaryFiles("hdfs:/Testing/*.zip")
files_data = zips.map(zip_extract).collect()
In the above code I returned a dictionary with filename in the zip as a key and the text data in each file as the value. you can change it however you want to suit your purposes.
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