Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
407 views
in Technique[技术] by (71.8m points)

ios - Type 'Any' Has no Subscript Members in xcode 8 Swift 3


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Try this:

let json = try JSONSerialization.jsonObject(with: data!, options:.allowFragments) as! [String:AnyObject]

Safe way:

do {
    if let json = try JSONSerialization.jsonObject(with: data!, options:.allowFragments) as? [String:Any] {
        print(json)
    }
} catch let err{
    print(err.localizedDescription)
}

You have to cast type Any to Swift dictionary type [String:AnyObject].

Edit: Swift 3
In swift 3 the purpose of AnyObject is more clarified. So more favourable Swift Dictionary type will be [String:Any].

Any is an alias for any data type.
AnyObject is an alias for any data type derived from a class.

For more info visit: https://craiggrummitt.com/2016/09/16/any-vs-anyobject-vs-nsobject-in-swift-3/


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...