Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
127 views
in Technique[技术] by (71.8m points)

When to use the double not (!!) operator in JavaScript

I understand what the double not operator does in JavaScript. I'm curious about it's use though and whether or not a recent assertion that I made is correct.

I said that if (!!someVar) is never meaningful nor is (!!someVar && ... because both the if and the && will cause someVar to be evaluated as a boolean so the !! is superfluous.

In fact, the only time that I could think of that it would be legitimate to use the double not operator is if you wanted to do a strict comparison to another boolean value (so maybe in return value that expects true or false explicitly).

Is this correct? I started to doubt myself when I noticed jQuery 1.3.2 used both if (!!someVar) and return !!someVar && ...

Does the double not have any actual effect in these situations?

My personal opinion is that it just leads to confusion. If I see an if statement, I know it's evaluating it as a boolean.

Question&Answers:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

In the context of if statements I'm with you, it is completely safe because internally, the ToBoolean operation will be executed on the condition expression (see Step 3 on the spec).

But if you want to, lets say, return a boolean value from a function, you should ensure that the result will be actually boolean, for example:

function isFoo () {
  return 0 && true;
}

console.log(isFoo()); // will show zero
typeof isFoo() == "number";

In conclusion, the Boolean Logical Operators can return an operand, and not a Boolean result necessarily:

The Logical AND operator (&&), will return the value of the second operand if the first is truly:

true && "foo"; // "foo"

And it will return the value of the first operand if it is by itself falsy:

NaN && "anything"; // NaN
0 && "anything"; // 0

On the other hand, the Logical OR operator (||) will return the value of the second operand, if the first one is falsy:

false || "bar"; // "bar"

And it will return the value of the first operand if it is by itself non-falsy:

"foo" || "anything"; // "foo"

Maybe it's worth mentioning that the falsy values are: null, undefined, NaN, 0, zero-length string, and of course false.

Anything else (that is not falsy, a Boolean object or a Boolean value), evaluated in boolean context, will return true.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...