For me, the most pythonic* way is the following which pretty much does the same thing but uses the +
operator for concatenating the individual characters in each string:
res = "".join(i + j for i, j in zip(u, l))
print(res)
# 'AaBbCcDdEeFfGgHhIiJjKkLlMmNnOoPpQqRrSsTtUuVvWwXxYyZz'
It is also faster than using two join()
calls:
In [5]: l1 = 'A' * 1000000; l2 = 'a' * 1000000
In [6]: %timeit "".join("".join(item) for item in zip(l1, l2))
1 loops, best of 3: 442 ms per loop
In [7]: %timeit "".join(i + j for i, j in zip(l1, l2))
1 loops, best of 3: 360 ms per loop
Faster approaches exist, but they often obfuscate the code.
Note: If the two input strings are not the same length then the longer one will be truncated as zip
stops iterating at the end of the shorter string. In this case instead of zip
one should use zip_longest
(izip_longest
in Python 2) from the itertools
module to ensure that both strings are fully exhausted.
*To take a quote from the Zen of Python: Readability counts.
Pythonic = readability for me; i + j
is just visually parsed more easily, at least for my eyes.
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