syntax - Are semicolons optional in Rust?

Question

Since semicolons are apparently optional in Rust, why, if I do this:

fn fn1() -> i32 {    
    let a = 1
    let b = 2
    3
}

I get the error:

error: expected one of `.`, `;`, `?`, or an operator, found `let`
 --> src/main.rs:3:9
  |
2 |         let a = 1
  |                  - expected one of `.`, `;`, `?`, or an operator here
3 |         let b = 2
  |         ^^^ unexpected token

Answer 1

They're not optional. Semicolons modify the behaviour of an expression statement so it should be a conscious decision whether you use them or not for a line of code.

Almost everything in Rust is an expression. An expression is something that returns a value. If you put a semicolon you are suppressing the result of this expression, which in most cases is what you want.

On the other hand, this means that if you end your function with an expression without a semicolon, the result of this last expression will be returned. The same can be applied for a block in a match statement.

You can use expressions without semicolons anywhere else a value is expected.

For example:

let a = {
    let inner = 2;
    inner * inner
};

Here the expression inner * inner does not end with a semicolon, so its value is not suppressed. Since it is the last expression in the block, its value will be returned and assigned to a. If you put a semicolon on this same line, the value of inner * inner won't be returned.

In your specific case, not suppressing the value of your let statement doesn't make sense, and the compiler is rightly giving you an error for it. In fact, let is not an expression.