Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
379 views
in Technique[技术] by (71.8m points)

php - Nullable return types in PHP7

PHP 7 introduces return type declarations. Which means I can now indicate the return value is a certain class, interface, array, callable or one of the newly hintable scalar types, as is possible for function parameters.

function returnHello(): string {
    return 'hello';
}

Often it happens that a value is not always present, and that you might return either something of some type, or null. While you can make parameters nullable by setting their default to null (DateTime $time = null), there does not appear to be a way to do this for return types. Is that indeed the case, or am I somehow not finding how to do it? These do not work:

function returnHello(): string? {
    return 'hello';
}

function returnHello(): string|null {
    return 'hello';
}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

PHP 7.1 Now supports nullable return types. The first RFC I linked to is the one they went for:

function nullOrString(int $foo) : ?string
{
    return $foo%2 ? "odd" : null;
}

old answer:

Since my comment was actually an answer to the question:

PHP 7 won't support nullable return-types just yet, but there's an RFC out to address just that, it aims to land in PHP 7.1. If it passes, the syntax would then affect all type-hints (both return types and type-hints):

public function returnStringOrNull(?array $optionalArray) : ?string
{
    if ($optionalArray) {
        return implode(', ', $optionalArray);//string returned here
    }
    return null;
}

There's also a competing RFC to add union types, which would be able to do the same thing, but would look different:

public function returnStringOrNull(array|null $optionalArray) : string|null
{
    if ($optionalArray) {
        return implode(', ', $optionalArray);//string returned here
    }
    return null;
}

For now, though, you'll have to write:

public function returnStringOrNull( array $optionalArray = null)
{
    if ($optionalArray) {
        return implode(', ', $optionalArray);
    }
}

Or just return an empty string to be consistent with the return type, and check falsy value:

public function returnStringOrNull( array $optionalArray = null) : string
{
    if ($optionalArray) {
        return implode(', ', $optionalArray);
    }
    return '';
}
//call
$string = $x->returnStringOrNull();
if (!$string) {
    $string = $x->returnStringOrNull(range(1, 10));
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...