Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
447 views
in Technique[技术] by (71.8m points)

r - Find start and end positions/indices of runs/consecutive values

Problem: Given an atomic vector, find the start and end indices of runs in the vector.

Example vector with runs:

x = rev(rep(6:10, 1:5))
# [1] 10 10 10 10 10  9  9  9  9  8  8  8  7  7  6

Output from rle():

rle(x)
# Run Length Encoding
#  lengths: int [1:5] 5 4 3 2 1
#  values : int [1:5] 10 9 8 7 6

Desired output:

#   start end
# 1     1   5
# 2     6   9
# 3    10  12
# 4    13  14
# 5    15  15

The base rle class doesn't appear to provide this functionality, but the class Rle and function rle2 do. However, given how minor the functionality is, sticking to base R seems more sensible than installing and loading additional packages.

There are examples of code snippets (here, here and on SO) which solve the slightly different problem of finding start and end indices for runs which satisfy some condition. I wanted something that would be more general, could be performed in one line, and didn't involve the assignment of temporary variables or values.

Answering my own question because I was frustrated by the lack of search results. I hope this helps somebody!

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Core logic:

# Example vector and rle object
x = rev(rep(6:10, 1:5))
rle_x = rle(x)

# Compute endpoints of run
end = cumsum(rle_x$lengths)
start = c(1, lag(end)[-1] + 1)

# Display results
data.frame(start, end)
#   start end
# 1     1   5
# 2     6   9
# 3    10  12
# 4    13  14
# 5    15  15

Tidyverse/dplyr way (data frame-centric):

library(dplyr)

rle(x) %>%
  unclass() %>%
  as.data.frame() %>%
  mutate(end = cumsum(lengths),
         start = c(1, dplyr::lag(end)[-1] + 1)) %>%
  magrittr::extract(c(1,2,4,3)) # To re-order start before end for display

Because the start and end vectors are the same length as the values component of the rle object, solving the related problem of identifying endpoints for runs meeting some condition is straightforward: filter or subset the start and end vectors using the condition on the run values.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...