Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
190 views
in Technique[技术] by (71.8m points)

python - Replace value for a selected cell in pandas DataFrame without using index

this is a rather similar question to this question but with one key difference: I'm selecting the data I want to change not by its index but by some criteria.

If the criteria I apply return a single row, I'd expect to be able to set the value of a certain column in that row in an easy way, but my first attempt doesn't work:

>>> d = pd.DataFrame({'year':[2008,2008,2008,2008,2009,2009,2009,2009], 
...                   'flavour':['strawberry','strawberry','banana','banana',
...                   'strawberry','strawberry','banana','banana'],
...                   'day':['sat','sun','sat','sun','sat','sun','sat','sun'],
...                   'sales':[10,12,22,23,11,13,23,24]})

>>> d
   day     flavour  sales  year
0  sat  strawberry     10  2008
1  sun  strawberry     12  2008
2  sat      banana     22  2008
3  sun      banana     23  2008
4  sat  strawberry     11  2009
5  sun  strawberry     13  2009
6  sat      banana     23  2009
7  sun      banana     24  2009

>>> d[d.sales==24]
   day flavour  sales  year
7  sun  banana     24  2009

>>> d[d.sales==24].sales = 100
>>> d
   day     flavour  sales  year
0  sat  strawberry     10  2008
1  sun  strawberry     12  2008
2  sat      banana     22  2008
3  sun      banana     23  2008
4  sat  strawberry     11  2009
5  sun  strawberry     13  2009
6  sat      banana     23  2009
7  sun      banana     24  2009

So rather than setting 2009 Sunday's Banana sales to 100, nothing happens! What's the nicest way to do this? Ideally the solution should use the row number, as you normally don't know that in advance!

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Many ways to do that

1

In [7]: d.sales[d.sales==24] = 100

In [8]: d
Out[8]: 
   day     flavour  sales  year
0  sat  strawberry     10  2008
1  sun  strawberry     12  2008
2  sat      banana     22  2008
3  sun      banana     23  2008
4  sat  strawberry     11  2009
5  sun  strawberry     13  2009
6  sat      banana     23  2009
7  sun      banana    100  2009

2

In [26]: d.loc[d.sales == 12, 'sales'] = 99

In [27]: d
Out[27]: 
   day     flavour  sales  year
0  sat  strawberry     10  2008
1  sun  strawberry     99  2008
2  sat      banana     22  2008
3  sun      banana     23  2008
4  sat  strawberry     11  2009
5  sun  strawberry     13  2009
6  sat      banana     23  2009
7  sun      banana    100  2009

3

In [28]: d.sales = d.sales.replace(23, 24)

In [29]: d
Out[29]: 
   day     flavour  sales  year
0  sat  strawberry     10  2008
1  sun  strawberry     99  2008
2  sat      banana     22  2008
3  sun      banana     24  2008
4  sat  strawberry     11  2009
5  sun  strawberry     13  2009
6  sat      banana     24  2009
7  sun      banana    100  2009

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...