LINQ to XML allows this to be much simpler, through three features:
- You can construct an object without knowing the document it's part of
- You can construct an object and provide the children as arguments
- If an argument is iterable, it will be iterated over
So here you can just do:
void Main()
{
List<string> list = new List<string>
{
"Data1", "Data2", "Data3"
};
XDocument doc =
new XDocument(
new XElement("file",
new XElement("name", new XAttribute("filename", "sample")),
new XElement("date", new XAttribute("modified", DateTime.Now)),
new XElement("info",
list.Select(x => new XElement("data", new XAttribute("value", x)))
)
)
);
doc.Save("Sample.xml");
}
I've used this code layout deliberately to make the code itself reflect the structure of the document.
If you want an element that contains a text node, you can construct that just by passing in the text as another constructor argument:
// Constructs <element>text within element</element>
XElement element = new XElement("element", "text within element");
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