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mysqldump - dump all mysql tables into separate files automagically?

I'd like to get dumps of each mysql table into separate files. The manual indicates that the syntax for this is

mysqldump [options] db_name [tbl_name ...]

Which indicates that you know the table names before hand. I could set up the script that knows each table name now, but say I add a new table down the road and forget to update the dump script. Then I'm missing dumps for one or more table.

Is there a way to automagically dump each existing table into a separate file? Or am I going to have to do some script-fu; query the database, get all the table names, and dump them by name.

If I go the script-fu route, what scripting langauges can access a mysql database?

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Here's a script that dumps table data as SQL commands into separate, compressed files. It does not require being on the MySQL server host, doesn't hard-code the password in the script, and is just for a specific db, not all db's on the server:

#!/bin/bash

# dump-tables-mysql.sh
# Descr: Dump MySQL table data into separate SQL files for a specified database.
# Usage: Run without args for usage info.
# Author: @Trutane
# Ref: http://stackoverflow.com/q/3669121/138325
# Notes:
#  * Script will prompt for password for db access.
#  * Output files are compressed and saved in the current working dir, unless DIR is
#    specified on command-line.

[ $# -lt 3 ] && echo "Usage: $(basename $0) <DB_HOST> <DB_USER> <DB_NAME> [<DIR>]" && exit 1

DB_host=$1
DB_user=$2
DB=$3
DIR=$4

[ -n "$DIR" ] || DIR=.
test -d $DIR || mkdir -p $DIR

echo -n "DB password: "
read -s DB_pass
echo
echo "Dumping tables into separate SQL command files for database '$DB' into dir=$DIR"

tbl_count=0

for t in $(mysql -NBA -h $DB_host -u $DB_user -p$DB_pass -D $DB -e 'show tables') 
do 
    echo "DUMPING TABLE: $DB.$t"
    mysqldump -h $DB_host -u $DB_user -p$DB_pass $DB $t | gzip > $DIR/$DB.$t.sql.gz
    tbl_count=$(( tbl_count + 1 ))
done

echo "$tbl_count tables dumped from database '$DB' into dir=$DIR"

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