A combination of list comprehensions and str
joins can do the job:
inf = float('inf')
A = [[0,1,4,inf,3],
[1,0,2,inf,4],
[4,2,0,1,5],
[inf,inf,1,0,3],
[3,4,5,3,0]]
print('
'.join([''.join(['{:4}'.format(item) for item in row])
for row in A]))
yields
0 1 4 inf 3
1 0 2 inf 4
4 2 0 1 5
inf inf 1 0 3
3 4 5 3 0
Using for-loops with indices is usually avoidable in Python, and is not considered "Pythonic" because it is less readable than its Pythonic cousin (see below). However, you could do this:
for i in range(n):
for j in range(n):
print '{:4}'.format(A[i][j]),
print
The more Pythonic cousin would be:
for row in A:
for val in row:
print '{:4}'.format(val),
print
However, this uses 30 print statements, whereas my original answer uses just one.
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