Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
705 views
in Technique[技术] by (71.8m points)

wpf - How to set Grid row and column positions programmatically

I have two Grids inside a Stackpanel. The first grid is named as GridX. Initially, inside the grid, there is a 2D array of Textboxes(RowDefs/ColumnDefs). The TextBox definition in XAML is

<TextBox x:Name="A1" Grid.Row="4" Grid.Column="5" TextAlignment="Center" />

I want to add a TextBlock programmatically in the same position as part of GridX.

The effect must be like this

<TextBlock Grid.Row="4" Grid.Column="5"
HorizontalAlignment="Left" VerticalAlignment="Top" Text="10" FontSize="8"/>

How to add this. I have tried this:

TextBlock tblock = new TextBlock();
GridX.SetColumn(tblock, cIndex);
GridX.SetRow(tblock, rIndex);

But failed.

Again I tried this:

int rIndex = Grid.GetRow(txtBox);
int cIndex = Grid.GetColumn(txtBox);                               

TextBlock tblock = new TextBlock();
tblock.VerticalAlignment = VerticalAlignment.Top;
tblock.HorizontalAlignment = HorizontalAlignment.Left;
tblock.FontSize = 8;
tblock.Text = rc[i, j - 1];

Grid.SetColumn(tblock, cIndex);
Grid.SetRow(tblock, rIndex);

txtBox.MaxLength = 1;    

Now the problem is that TextBlock is not visible. TextBox hides it. I appreciate your help.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

For attached properties you can either call SetValue on the object for which you want to assign the value:

tblock.SetValue(Grid.RowProperty, 4);

Or call the static Set method (not as an instance method like you tried) for the property on the owner type, in this case SetRow:

Grid.SetRow(tblock, 4);

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...