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assembly - What are the sizes of tword, oword and yword operands?

What are the sizes of tword, oword and yword operands, as used in the NASM/YASM manual? And on a related note, is there a trick or underlying idea to these names? Is there a way by which bigger word sizes are given logical names?

I know that while word sizes may differ between systems, a NASM word is 2 bytes, dword is double that (4 bytes), qword is a quad word (8 bytes), but... is tword a triple word (6 bytes)? And for oword and yword I can't even think of a plausible meaning.

Note that it is probably an easy question, but I couldn't find an answer. In the NASM and YASM manuals these sizes are not explained, not even at the DQ, DT, DY, RESQ, REST, RESY pseudo-instructions. I read somewhere that MASM uses a similar system, but could not find anything on that either.


Edit: Based on the answers, this is the complete list:

  • 1 byte (8 bit): byte, DB, RESB
  • 2 bytes (16 bit): word, DW, RESW
  • 4 bytes (32 bit): dword, DD, RESD
  • 8 bytes (64 bit): qword, DQ, RESQ
  • 10 bytes (80 bit): tword, DT, REST
  • 16 bytes (128 bit): oword, DO, RESO, DDQ, RESDQ
  • 32 bytes (256 bit): yword, DY, RESY
  • 64 bytes (512 bit): zword, DZ, RESZ
See Question&Answers more detail:os

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Looking at the nasm source, it looks like:

  • 'oword'/'DO' is 8 times as big as "word" (O for "octoword"), synonymous with dqword ("double-quad"); that would be 128 bits, corresponding to the size of an SSE vector register.
  • 'tword'/'DT' is 80 bits (T for "ten bytes"), the full size of an Intel x87 floating point register.
  • 'yword'/'DY' is 256 bits, and the Y is presumably mnemonic for the YMM names of the 256-bit vector registers in the Intel AVX extensions.
  • 'zword'/'DZ' is 512 bits, Z for the ZMM names of the 512-bit vector registers in the Intel AVX-512 extensions.

So, it's not exactly a logical naming convention; "it just growed".


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