python - Removing elements from an array that are in another array

Question

Say I have these 2D arrays A and B.

How can I remove elements from A that are in B. (Complement in set theory: A-B)

A=np.asarray([[1,1,1], [1,1,2], [1,1,3], [1,1,4]])
B=np.asarray([[0,0,0], [1,0,2], [1,0,3], [1,0,4], [1,1,0], [1,1,1], [1,1,4]])
#output = [[1,1,2], [1,1,3]]

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To be more precise, I would like to do something like this.

data = some numpy array
label = some numpy array
A = np.argwhere(label==0) #[[1 1 1], [1 1 2], [1 1 3], [1 1 4]]
B = np.argwhere(data>1.5) #[[0 0 0], [1 0 2], [1 0 3], [1 0 4], [1 1 0], [1 1 1], [1 1 4]]
out = np.argwhere(label==0 and data>1.5) #[[1 1 2], [1 1 3]]

Answer 1

there is a easy solution with list comprehension,

A = [i for i in A if i not in B]

Result

[[1, 1, 2], [1, 1, 3]]

List comprehension it's not removing the elements from the array, It's just reassigning,

if you want to remove the elements use this method

for i in B:
     if i in A:
     A.remove(i)