bash - How do I pass on script arguments that contain quotes/spaces?

Question

I'm trying to write a script notify-finish that can be prepended to any command. When done, it will run the command given by the arguments following, then email the user when the command is complete. Here's what I have:

PROG=$1
# Run command given by arguments
$@
ECODE=$?
echo -e "Subject: `hostname`: $PROG finished
To: <$USER>

Exited with $ECODE
" | sendmail $USER

This works most of the time, but when arguments contain spaces, the quoting is stripped off.

Working example:

notify-finished rsync -avz source/ user@remote:dest/

Failing example:

notify-finished rsync -avz -e 'ssh -c blowfish' source/ user@remote:dest/

In the second case, $@ is expanded out to rsync -avz -e ssh -c blowfish source user@remote:dest/, missing the single quotes. It does not work with double-quotes either, nor with $*.

After reading other posts I tried putting the command in an array, but I get the exact same issue:

CMD=(notify-finished rsync -avz -e 'ssh -c blowfish' source/ user@remote:dest/)
${CMD[@]}

How do I make this work for all arguments?

Answer 1

Use "$@" with quotes:

prog="$1"
"$@"
ecode="$?"
echo "$prog exited with $ecode"

This will pass each argument exactly as it was received. If you don't include the quotes, each element will be split according to $IFS:

• "$@" is like "$1" "$2" "$3" ..., passing each element as a separate argument.
• "$*" is like "$1 $2 $3 ...", passing all elements concatenated as a single argument
• $* and $@ is like $1 $2 $3 ..., breaking up each element on whitespace, expanding all globs, and passing each resulting word as a separate element ($IFS).

The same is true for arrays, such as "${array[@]}" and "${array[*]}"