Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
835 views
in Technique[技术] by (71.8m points)

selenium - Equivalent of Firebug's "Copy XPath" in Internet Explorer?

I have an Internet Explorer only web application.

I'm exploring what we can do to automate the testing.

Selenium looks like a good tool, but to be able to activate links etc. I need to tell it where they are. The application wasn't built with this kind of testing in mind, so there generally aren't id attributes on the key elements.

No problem, I think, I can use XPath expressions. But finding the correct XPath for, say, a button, is a royal pain if done by inspecting the source of the page.

With Firefox / Firebug, I can select the element then use "Copy XPath" to get the expression.

I have the IE Developer Toolbar and it's frustratingly close. I can click to select the element of interest and display all sorts of information about it. but I can't see any convenient way of determining the XPath for it.

So is there any way of doing this with IE?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

I would use bookmarklets. I have one XPath related, but I don't know if it works in IE. I gotta go but I will test it and give it if it works on IE.

Two bookmarklet sites for Web developers from my bookmarks: Subsimple's bookmarklets and Squarefree's Bookmarklets. Lot of useful things there...

[EDIT] OK, I am back. The bookmarklet I had was for FF only, and wasn't optimal. I finally rewrote it, although using ideas from the original one. Can't find back where I found it.

Expanded JS:

function getNode(node)
{
  var nodeExpr = node.tagName;
  if (nodeExpr == null)  // Eg. node = #text
    return null;
  if (node.id != '')
  {
    nodeExpr += "[@id='" + node.id + "']";
    // We don't really need to go back up to //HTML, since IDs are supposed
    // to be unique, so they are a good starting point.
    return "/" + nodeExpr;
  }
// We don't really need this
//~   if (node.className != '')
//~   {
//~     nodeExpr += "[@class='" + node.className + "']";
//~   }
  // Find rank of node among its type in the parent
  var rank = 1;
  var ps = node.previousSibling;
  while (ps != null)
  {
    if (ps.tagName == node.tagName)
    {
      rank++;
    }
    ps = ps.previousSibling;
  }
  if (rank > 1)
  {
    nodeExpr += '[' + rank + ']';
  }
  else
  {
    // First node of its kind at this level. Are there any others?
    var ns = node.nextSibling;
    while (ns != null)
    {
      if (ns.tagName == node.tagName)
      {
        // Yes, mark it as being the first one
        nodeExpr += '[1]';
        break;
      }
      ns = ns.nextSibling;
    }
  }
  return nodeExpr;
}

var currentNode;
// Standard (?)
if (window.getSelection != undefined) 
  currentNode = window.getSelection().anchorNode;
// IE (if no selection, that's BODY)
else 
  currentNode = document.selection.createRange().parentElement();
if (currentNode == null)
{
  alert("No selection");
  return;
}
var path = [];
// Walk up the Dom
while (currentNode != undefined)
{
  var pe = getNode(currentNode);
  if (pe != null)
  {
    path.push(pe);
    if (pe.indexOf('@id') != -1)
      break;  // Found an ID, no need to go upper, absolute path is OK
  }
  currentNode = currentNode.parentNode;
}
var xpath = "/" + path.reverse().join('/');
alert(xpath);
// Copy to clipboard
// IE
if (window.clipboardData) clipboardData.setData("Text", xpath);
// FF's code to handle clipboard is much more complex 
// and might need to change prefs to allow changing the clipboard content.
// I omit it here as it isn't part of the original request.

You have to select the element and activate the bookmarklet to get its XPath.

Now, the bookmarklet versions (thanks to Bookmarklet Builder):

IE
(I had to break it in two parts, because IE doesn't like very long bookmarklets (max size varies depending on IE versions!). You have to activate the first one (function def) then the second one. Tested with IE6.)

javascript:function getNode(node){var nodeExpr=node.tagName;if(!nodeExpr)return null;if(node.id!=''){nodeExpr+="[@id='"+node.id+"']";return "/"+nodeExpr;}var rank=1;var ps=node.previousSibling;while(ps){if(ps.tagName==node.tagName){rank++;}ps=ps.previousSibling;}if(rank>1){nodeExpr+='['+rank+']';}else{var ns=node.nextSibling;while(ns){if(ns.tagName==node.tagName){nodeExpr+='[1]';break;}ns=ns.nextSibling;}}return nodeExpr;}
javascript:function o__o(){var currentNode=document.selection.createRange().parentElement();var path=[];while(currentNode){var pe=getNode(currentNode);if(pe){path.push(pe);if(pe.indexOf('@id')!=-1)break;}currentNode=currentNode.parentNode;}var xpath="/"+path.reverse().join('/');clipboardData.setData("Text", xpath);}o__o();

FF

javascript:function o__o(){function getNode(node){var nodeExpr=node.tagName;if(nodeExpr==null)return null;if(node.id!=''){nodeExpr+="[@id='"+node.id+"']";return "/"+nodeExpr;}var rank=1;var ps=node.previousSibling;while(ps!=null){if(ps.tagName==node.tagName){rank++;}ps=ps.previousSibling;}if(rank>1){nodeExpr+='['+rank+']';}else{var ns=node.nextSibling;while(ns!=null){if(ns.tagName==node.tagName){nodeExpr+='[1]';break;}ns=ns.nextSibling;}}return nodeExpr;}var currentNode=window.getSelection().anchorNode;if(currentNode==null){alert("No selection");return;}var path=[];while(currentNode!=undefined){var pe=getNode(currentNode);if(pe!=null){path.push(pe);if(pe.indexOf('@id')!=-1)break;}currentNode=currentNode.parentNode;}var xpath="/"+path.reverse().join('/');alert(xpath);}o__o();

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...