I wonder how the following can be done
void f(string &&s) {
std::string i(move(s));
/* other stuff */
}
int main() {
std::string s;
bind(f, s)(); // Error.
bind(f, move(s))(); // Error.
bind(f, ref(s))(); // Error.
}
How can I pass an rvalue reference and store it as an rvalue reference (possibly wrapped) in the call wrapper? I know I can manually write up a class like std::reference_wrapper<>
that has a conversion function to T&&
, but I would rather want to avoid that and use Standard technology.
I implemented it like AProgrammer recommends:
template<typename T> struct adv {
T t;
explicit adv(T &&t):t(forward<T>(t)) {}
template<typename ...U> T &&operator()(U &&...) {
return forward<T>(t);
}
};
template<typename T> adv<T> make_adv(T &&t) {
return adv<T>{forward<T>(t)};
}
namespace std {
template<typename T>
struct is_bind_expression< adv<T> > : std::true_type {};
}
Now I can say
void f(string &&s) {
std::string i(move(s));
/* other stuff */
}
int main() {
std::string s;
bind(f, make_adv(move(s)))(); // Works!
}
If we pass an lvalue to make_adv
, it will forward it as an lvalue referring to the input argument, so it can be used as a replacement for std::ref
, in this case.
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