rust - Why does passing a closure to function which accepts a function pointer not work?

Question

In the second edition of The Rust Programming Language (emphasis mine):

Function pointers implement all three of the closure traits (Fn, FnMut, and FnOnce), so you can always pass a function pointer as an argument for a function that expects a closure. It’s best to write functions using a generic type and one of the closure traits so your functions can accept either functions or closures.

Passing a closure to a function which accepts a function pointer as an argument doesn't compile:

fn main() {
    let a = String::from("abc");

    let x = || println!("{}", a);

    fn wrap(c: fn() -> ()) -> () {
        c()
    }

    wrap(x);
}

error[E0308]: mismatched types
  --> src/main.rs:10:10
   |
10 |     wrap(x);
   |          ^ expected fn pointer, found closure
   |
   = note: expected type `fn()`
              found type `[closure@src/main.rs:4:13: 4:33 a:_]`

Why does this not work?

Answer 1

There are certain cases where you can pass a closure as a function pointer. This works:

fn main() {
    let x = || {
        let a = String::from("abc");
        println!("{}", a);
    };

    fn wrap(c: fn()) {
        c()
    }

    wrap(x);
}

The important difference is that the closure is not allowed to capture anything from its environment. That means that we had to prevent the String from crossing the closure boundary.

Any closure that doesn't capture environment can be trivially rewritten as a anonymous standalone function and then converted into a function pointer.

Once you add an environment, it is no longer convertible and everything from the existing answer applies.

Note that stating -> () is non-idiomatic as that's the default if nothing is specified.

See also:

• RFC 1558 - Closure to fn Coercion