Do you like to use private APIs? If yes,
UIView* view = thatItem.view;
return [view convertRect:view.bounds toView:nil];
Of course no one wants this when targeting the AppStore. A more unreliable method, and also uses undocumented features, but will pass Apple's test, is to loop through the subviews to look for the corresponding button item.
NSMutableArray* buttons = [[NSMutableArray alloc] init];
for (UIControl* btn in theToolbarOrNavbar.subviews)
if ([btn isKindOfClass:[UIControl class]])
[buttons addObject:btn];
UIView* view = [buttons objectAtIndex:index];
[buttons release];
return [view convertRect:view.bounds toView:nil];
The index
is the index to your bar item in the array of .items
, after removing all blank items. This assumes the buttons are arranged in increasing order, which may not be. A more reliable method is to sort the buttons
array in increasing .origin.x
value. Of course this still assumes the bar button item must inherit the UIControl class, and are direct subviews of the toolbar/nav-bar, which again may not be.
As you can see, there are a lot of uncertainty when dealing with undocumented features. However, you just want to pop up something under the finger right? The UIBarButtonItem's .action
can be a selector of the form:
-(void)buttonClicked:(UIBarButtonItem*)sender event:(UIEvent*)event;
note the event argument — you can obtain the position of touch with
[[event.allTouches anyObject] locationInView:theWindow]
or the button view with
[[event.allTouches anyObject] view]
Therefore, there's no need to iterate the subviews or use undocumented features for what you want to do.
与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…