It is not possible using a selenium webdriver API, but you can execute a javascript code to get all attributes:
driver.execute_script('var items = {}; for (index = 0; index < arguments[0].attributes.length; ++index) { items[arguments[0].attributes[index].name] = arguments[0].attributes[index].value }; return items;', element)
Demo:
>>> from selenium import webdriver
>>> from pprint import pprint
>>> driver = webdriver.Firefox()
>>> driver.get('https://stackoverflow.com')
>>>
>>> element = driver.find_element_by_xpath('//div[@class="network-items"]/a')
>>> attrs = driver.execute_script('var items = {}; for (index = 0; index < arguments[0].attributes.length; ++index) { items[arguments[0].attributes[index].name] = arguments[0].attributes[index].value }; return items;', element)
>>> pprint(attrs)
{u'class': u'topbar-icon icon-site-switcher yes-hover js-site-switcher-button js-gps-track',
u'data-gps-track': u'site_switcher.show',
u'href': u'//stackexchange.com',
u'title': u'A list of all 132 Stack Exchange sites'}
For completeness sake, an alternative solution would be to get the tag's outerHTML
and parse the attributes using an HTML parser. Example (using BeautifulSoup
):
>>> from bs4 import BeautifulSoup
>>> html = element.get_attribute('outerHTML')
>>> attrs = BeautifulSoup(html, 'html.parser').a.attrs
>>> pprint(attrs)
{u'class': [u'topbar-icon',
u'icon-site-switcher',
u'yes-hover',
u'js-site-switcher-button',
u'js-gps-track'],
u'data-gps-track': u'site_switcher.show',
u'href': u'//stackexchange.com',
u'title': u'A list of all 132 Stack Exchange sites'}
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