go - Golang defer behavior

Question

Effective Go states the following regarding defer:

The arguments to the deferred function (which include the receiver if the function is a method) are evaluated when the defer executes, not when the call executes. Besides avoiding worries about variables changing values as the function executes, this means that a single deferred call site can defer multiple function executions. Here's a silly example.

for i := 0; i < 5; i++ {
    defer fmt.Printf("%d ", i)
}

Deferred functions are executed in LIFO order, so this code will cause 4 3 2 1 0 to be printed when the function returns.

This example confuses me. If parameters are evaluated when the defer call is executed, then the defers in the for loop should print 5 5 5 5 5 since the defers will be called when the for loop ends, and at that time i would be 5. Evaluating defers at the end of the for loop will thus result in 5 for all calls.

Am I missing something here?

Answer 1

Waitting for answers