Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
523 views
in Technique[技术] by (71.8m points)

xslt - XSL Transformation in Java with parameters

I have a xsl file where i need to use parameters from an external source. I am using Java and my code looks something like this:

TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer xsltTransformer = transformerFactory.newTransformer(xsltSource);
xsltTransformer.setParameter(parameterName, parameterValue);

However, an exception is thrown at the 2nd line - Variable or parameter 'variable_name' is undefined. I realize that XSL is compiled and is probably compiled when the transformer is created.

So, how do i pass parameters to my transformation? How is the setParameter method supposed to be used?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

If you pass a parameter like:

transformer.setParameter("render_id", "1234");

the parameter can be picked up by the transform:

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >

<xsl:output method="xml" encoding="UTF-8" omit-xml-declaration="yes"/>

<!-- Receives the id of the menu being rendered. -->
<xsl:param name="render_id" />

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...