Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
212 views
in Technique[技术] by (71.8m points)

python - How to use Pandas rolling_* functions on a forward-looking basis

Suppose I have a time series:

In[138] rng = pd.date_range('1/10/2011', periods=10, freq='D')
In[139] ts = pd.Series(randn(len(rng)), index=rng)
In[140]
Out[140]:
2011-01-10    0
2011-01-11    1
2011-01-12    2
2011-01-13    3
2011-01-14    4
2011-01-15    5
2011-01-16    6
2011-01-17    7
2011-01-18    8
2011-01-19    9
Freq: D, dtype: int64

If I use one of the rolling_* functions, for instance rolling_sum, I can get the behavior I want for backward looking rolling calculations:

In [157]: pd.rolling_sum(ts, window=3, min_periods=0)
Out[157]: 
2011-01-10     0
2011-01-11     1
2011-01-12     3
2011-01-13     6
2011-01-14     9
2011-01-15    12
2011-01-16    15
2011-01-17    18
2011-01-18    21
2011-01-19    24
Freq: D, dtype: float64

But what if I want to do a forward-looking sum? I've tried something like this:

In [161]: pd.rolling_sum(ts.shift(-2, freq='D'), window=3, min_periods=0)
Out[161]: 
2011-01-08     0
2011-01-09     1
2011-01-10     3
2011-01-11     6
2011-01-12     9
2011-01-13    12
2011-01-14    15
2011-01-15    18
2011-01-16    21
2011-01-17    24
Freq: D, dtype: float64

But that's not exactly the behavior I want. What I am looking for as an output is:

2011-01-10    3
2011-01-11    6
2011-01-12    9
2011-01-13    12
2011-01-14    15
2011-01-15    18
2011-01-16    21
2011-01-17    24
2011-01-18    17
2011-01-19    9

ie - I want the sum of the "current" day plus the next two days. My current solution is not sufficient because I care about what happens at the edges. I know I could solve this manually by setting up two additional columns that are shifted by 1 and 2 days respectively and then summing the three columns, but there's got to be a more elegant solution.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Why not just do it on the reversed Series (and reverse the answer):

In [11]: pd.rolling_sum(ts[::-1], window=3, min_periods=0)[::-1]
Out[11]:
2011-01-10     3
2011-01-11     6
2011-01-12     9
2011-01-13    12
2011-01-14    15
2011-01-15    18
2011-01-16    21
2011-01-17    24
2011-01-18    17
2011-01-19     9
Freq: D, dtype: float64

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...